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(4-3x-x^2)/(x^2-1)=x
We move all terms to the left:
(4-3x-x^2)/(x^2-1)-(x)=0
Domain of the equation: (x^2-1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x^2!=1
x^2!=1/
x^2!=√1/
x!=1
x∈R
(4-3x-x^2)/(x^2-1)-1x=0
We multiply all the terms by the denominator
(4-3x-x^2)-1x*(x^2-1)=0
We multiply parentheses
(4-3x-x^2)-x^3+1x=0
We get rid of parentheses
-x^2-x^3-3x+1x+4=0
We do not support expression: x^3
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